The kinetic energy of a body of mass 0.5 kg and momentum 30 kgms−1 is ___ J.
The correct option is C. 900
Given: Momentum, p=30 kgms−1, m=0.5 kg
Let v be the velocity of the body.
We know kinetic energy, K.E=12mv2 and momentum, p=mv⇒v=pm
So by substituting the value of v in the expression of K.E,
K.E=12 m × (pm)2 =p22m
∴K.E=p22m =3022×0.5 =900 J.