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Question

The kinetic energy of a body of mass 0.5 kg and momentum 30 kgms−1 is ___ J.

A
1500
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B
4500
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C
900
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D
450
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Solution

The correct option is C. 900

Given: Momentum, p=30 kgms1, m=0.5 kg

Let v be the velocity of the body.

We know kinetic energy, K.E=12mv2 and momentum, p=mvv=pm

So by substituting the value of v in the expression of K.E,

K.E=12 m × (pm)2 =p22m

K.E=p22m =3022×0.5 =900 J.


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