The kinetic energy of a body of mass 0.5 kg and momentum 30 kgms−1 is
Given: Momentum, p=30 kgms−1, m=0.5 kg
We know kinetic energy, K.E=12mv2 and momentum, p=mv⇒v=pm
So by substituting the value of v in the expression of K.E,
K.E=12 m × (pm)2 =p22m
∴K.E=p22m =3022×.5 =900 J