The kinetic energy of a charged particle decreases by 10 J as it moves from a point at potential 100 V to a point at potential 200 V. Find the charge on the particle.

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Solution

By work-energy theorem,
Change in K.E. = Amount of work done
Change in K.E. = 10 J
Let the charge on the particle be q.
Change in potential, $∆ V$ = (200 − 100) V
Work done = $∆ V \times q$
$\Rightarrow 10 = (200 - 100) \times q \Rightarrow 100 \times q = 10 \Rightarrow q = \frac{10}{100} = 0.1 C$

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The kinetic energy of a charged particle decreases by 10 J as it moves from a point at potential 100 V to a point at potential 200 V. Find the charge on the particle.

By work-energy theorem, Change in K.E. = Amount of work done Change in K.E. = 10 J Let the charge on the particle be q. Change in potential, ∆V = (200 − 100) V Work done = ∆V×q ⇒10=(200-100)×q⇒100×q=10⇒q=10100=0.1 C