The kinetic energy of a harmonic oscillator is K-K0cos2- t- The maximum potential energy of the particle is

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Potential Energy Formulae

The kinetic e...

Question

The kinetic energy of a harmonic oscillator is $K = K_{0} cos 2 ω t$ . The maximum potential energy of the particle is

zero

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\frac{K_{0}}{2}

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K_{0}

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2 K

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Solution

The correct option is D $K_{0}$
In SHM, T.E= Max K.E=Max P.E. From this, we can say that maximum P.E will be Equal to maximum K.E, which in this case is $K_{0}$ , because maximum value of cos function is 1. Option C is correct.

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The kinetic energy of a harmonic oscillator is K=K0cos2ωt. The maximum potential energy of the particle is

The correct option is D K0In SHM, T.E= Max K.E=Max P.E. From this, we can say that maximum P.E will be Equal to maximum K.E, which in this case is K0, because maximum value of cos function is 1. Option C is correct.

The kinetic energy of a harmonic oscillator is $K = K_{0} cos 2 ω t$ . The maximum potential energy of the particle is

The correct option is D $K_{0}$
In SHM, T.E= Max K.E=Max P.E. From this, we can say that maximum P.E will be Equal to maximum K.E, which in this case is $K_{0}$ , because maximum value of cos function is 1. Option C is correct.