You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Damped Oscillations

The kinetic e...

Question

The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is

[Haryana CEE 1996; AFMC 1998]

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A

At mean position , the kinetic energy is maximum.

Hence $\frac{1}{2} m a^{2} ω^{2} = 16$

On putting the values we get

$ω = 10 \Rightarrow T = \frac{2 π}{ω} = \frac{π}{5}$ sec

Suggest Corrections

Similar questions

The K.E of a body in S.H.M is 16J when it is at mean position. If the amplitude of oscillations is 25 cm and mass of body m is 5 kg, the time period of its oscillations is

Q. A point particle of mass

0.1 k g

is executing S.H.M. of amplitude of

0.1 m

. When the particle passes through the mean position, its kinetic energy is

8 \times 10^{- 3} J o u l e

. Obtain the equation of motion of this particle if this initial phase of oscillation is

45^{\circ}

Q. A particle of mass

400 g

is executing SHM of amplitude

0.4 m

. When it passes through the mean position, its kinetic energy is

32 \times 10^{- 3} J

. If the initial phase of oscillation is

\frac{π}{4}

, then the equation of motion of the particle is

Q. A point particle of mass

0.1 k g

is executing S.H.M of amplitude of

0.1 m

. When the particle passes through the mean position, its kinetic energi is

18 \times 10^{- 3} J

. The equation of motion of this particle when the initial phase of oscillation is

45^{o}

can be given by :

Q. Amplitude of oscillation of a particle that executes S.H.M. is 2 cm. Its displacement from its mean position in a time equal to 1/6th of its time period is

Join BYJU'S Learning Program

The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is [Haryana CEE 1996; AFMC 1998]

The correct option is A At mean position , the kinetic energy is maximum. Hence 12ma2ω2=16 On putting the values we get ω=10⇒T=2πω=π5 sec

The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is

[Haryana CEE 1996; AFMC 1998]

The correct option is A

At mean position , the kinetic energy is maximum.

Hence $\frac{1}{2} m a^{2} ω^{2} = 16$

On putting the values we get

$ω = 10 \Rightarrow T = \frac{2 π}{ω} = \frac{π}{5}$ sec