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Standard XII

Physics

Damped Oscillations

The kinetic e...

Question

The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is

[Haryana CEE 1996; AFMC 1998]

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Solution

The correct option is A

At mean position , the kinetic energy is maximum.

Hence $\frac{1}{2} m a^{2} ω^{2} = 16$

On putting the values we get

$ω = 10 \Rightarrow T = \frac{2 π}{ω} = \frac{π}{5}$ sec

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The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is [Haryana CEE 1996; AFMC 1998]

The correct option is A At mean position , the kinetic energy is maximum. Hence 12ma2ω2=16 On putting the values we get ω=10⇒T=2πω=π5 sec

The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of its oscillation is

[Haryana CEE 1996; AFMC 1998]

The correct option is A

At mean position , the kinetic energy is maximum.

Hence $\frac{1}{2} m a^{2} ω^{2} = 16$

On putting the values we get

$ω = 10 \Rightarrow T = \frac{2 π}{ω} = \frac{π}{5}$ sec