The kinetic energy of α - particle emitted in the α - decay of 88Ra226 is [ given, mass number of Ra = 222 u ]
A
5.201 Me V
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B
3.301 Me V
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C
6.023 MeV
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D
4.871 MeV
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Solution
The correct option is D 4.871 MeV 88Ra226→R222n+2H4eQ=[226.02540−222.01750−4.00260]×931.5Mev=0.0053×931.5=4.94MevK.E=(A−4)QA=226−4226×4.94=4.85MevQ=4.94Mev,K.E=4.85Mev