The kinetic energy of an electron in the first Bhor orbit of hydrogen is :

13.6

e V

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6.8

e V

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- 13.6

e V

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27

e V

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Solution

The correct option is A $13.6$ $e V$
KE $= -$ (total energy)
The energy of an electron in the first Bohr orbit of $H$ atom is $- 13.6 e V$
KE $=$ $13.6 e v$

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The kinetic energy of an electron in the first Bhor orbit of hydrogen is :

The correct option is A 13.6 eVKE =− (total energy)The energy of an electron in the first Bohr orbit of H atom is −13.6eVKE = 13.6ev

The correct option is A $13.6$ $e V$
KE $= -$ (total energy)
The energy of an electron in the first Bohr orbit of $H$ atom is $- 13.6 e V$
KE $=$ $13.6 e v$