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Question

The kinetic energy of an electron is 5 eV. Calculate the de-Broglie wavelength associated with it. (h=6.6×1034 Js, me=9.1×1031 kg)

A
5.47 ˚A
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B
10.9 ˚A
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C
2.7 ˚A
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D
None of these
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Solution

The correct option is A 5.47 ˚A
de Broglie wavelength is given by,
λ=h2meEk

Here, Ek is kinetic energy and me is mass of the electron.
λ=6.6×10342×9.1×1031×5×1.6×1019

λ=5.469×1010 m5.47 ˚A

Hence, (A) is the correct answer.

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