The kinetic energy of an electron is 9.1×10−25J. Calculate the de Broglie wavelength for the same. (Planck's constant,h=6.6×10−34Js,mass of electron=9.1×10−31kg)
A
0.51×10−5m
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B
0.51×10−6m
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C
0.51×10−7m
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D
0.51×10−8m
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Solution
The correct option is B0.51×10−6m Given: Kinetic energy(K.E.)=9.1×10−25J Mass of electron(me)=9.1×10−31kgPlanck's constant(h)=6.6×10−34Js
We know, de Broglie wavelength(λ)=h√2K.E.me=6.6×10−34J−sec√2×9.1×10−25×9.1×10−31=0.51×10−6m