The kinetic energy of an electron, which is accelerated in the potential difference of $100 V$ , is

1.6 \times 10^{- 10} J

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1.6 \times 10^{8} J

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1.6 \times 10^{- 17} J

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1.6 \times 10^{- 18} J

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Solution

The correct option is C $1.6 \times 10^{- 17} J$
eV i.e. electron volt is the unit of energy defined as the kinetic energy of an electron accelerated in the potential difference of V volt $&$ e is charg of electron.
Thus acc. to question
K.E.= $e \times 100 V$
K.E.= $1.6 \times 10^{- 19} \times 100 V$
K.E.= $1.6 \times 10^{- 17}$

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The kinetic energy of an electron, which is accelerated in the potential difference of 100 V, is

The correct option is C 1.6×10−17JeV i.e. electron volt is the unit of energy defined as the kinetic energy of an electron accelerated in the potential difference of V volt & e is charg of electron.Thus acc. to questionK.E.=e×100VK.E.=1.6×10−19×100VK.E.=1.6×10−17

The kinetic energy of an electron, which is accelerated in the potential difference of $100 V$ , is