Question

The Kinetic energy of an object is K. If its velocity is doubled, then its kinetic energy will be

• A. $K$
• B. $2K$
• C. $4K$
• D. $\frac{K}{4}$

Answer 1

The correct option is C $4K$

Kinetic energy is given as:
$K.E=\frac{1}{2}m{v}^{2}K=\frac{1}{2}m{v}^2{K}^{\prime }=\frac{1}{2}m{v}^{{}^{\prime }2}{v}^{\prime }=2v{K}^{\prime }=\frac{1}{2}m(2v{)}^2=4\left(\frac{1}{2}m{v}^2\right)K^{\prime }=4K$