The kinetic energy of one mole of hydrogen gas at $127^{o} C$ in $c a l / m o l$ is __________.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

600

No worries! We‘ve got your back. Try BYJU‘S free classes today!

900

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1200

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B 1200
For kinetic energy,

$K E = \frac{3}{2} R T$
$K E = \frac{3 \times 2 \times 400}{2} = 1200 c a l / m o l$

Note: $127^{o} C = 400 K$

Suggest Corrections

Similar questions

127^{o} C

R =

c a l m o l

^{- 1}

K

^{- 1}

{m o l}^{- 1} K^{- 1}

The kinetic energy of 1 mole of oxygen molecules in $c a l m o l^{- 1}$ at $27^{\circ} C$ is__.

27^{o} C

=

N_{2}

27^{0} C

^{0} C

Join BYJU'S Learning Program