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Relating Translational KE and T

The kinetic e...

Question

The kinetic energy of one mole of hydrogen gas at $127^{o} C$ in $c a l / m o l$ is __________.

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600

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900

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1200

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Solution

The correct option is B 1200
For kinetic energy,

$K E = \frac{3}{2} R T$
$K E = \frac{3 \times 2 \times 400}{2} = 1200 c a l / m o l$

Note: $127^{o} C = 400 K$

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127^{o} C

R =

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^{- 1}

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The kinetic energy of 1 mole of oxygen molecules in $c a l m o l^{- 1}$ at $27^{\circ} C$ is__.

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^{0} C

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