Question

The kinetic energy $T$ of a particle moving along a circle of radius $R$ depends on the distance covered as $T=a{s}^2$. The force acting on the particle is:

• A. $\frac{2a{s}^2}{R}$
• B. $2as{(1+\frac{s^2}{R})}^{\frac{1}{2}}$
• C. $2as$
• D. $2a\frac{R^2}{s}$

Answer 1

Answer: (A)

$\frac{2a{s}^2}{R}$

$KE=a{s}^2$

$\Rightarrow \frac{1}{2}m{v}^2=a{s}^2$

$\Rightarrow \frac{m{v}^2}{R}=\frac{2a{s}^2}{R}$