The king, queen and jack of clubs are removed from a deck of $52$ playing cards and the remaining cards are shuffled. A card is drawn from the remaining cards. Find the probability of getting a card of queen of diamond.

Open in App

Solution

No. of all possible outcomes $= 52 - 3 = 49$
There is only one queen of diamond
$∴$ Required probability $= \frac{1}{49}$

Suggest Corrections

Similar questions

The king, queen and jack of clubs are removed from a deck of $52$ playing cards and the remaining cards are shuffled. A card is drawn from the remaining cards. Find the probability of getting a card is (i) heart (ii) queen (iii) clubs.

Q. The king, queen and jack of clubs are removed from a deck of

52

playing cards and the remaining cards are shuffled. A card is drawn from the remaining cards. Find the probability of getting a card of
A King.

Q. The king, queen and jack of clubs are removed form a deck of 52 playing cards and the remaining cards are shuffled. A card is drawn from the remaining cards. Find the probability of getting a card of (i) heart (ii) queen (iii) clubs.

Q. The king, queen and jack of clubs are removed from a deck of 52 playing cards and then shuffled. Find the probability of getting an '8’ of red color if a card is drawn from the remaining cards.

Q. The king, queen and jack of diamonds are removed from a pack of 52 playing cards and the pack is well shuffled. A card is drawn from the remaining cards. Find the probability of getting a card of

(i) diamond

(ii) a jack

Join BYJU'S Learning Program

The king, queen and jack of clubs are removed from a deck of 52 playing cards and the remaining cards are shuffled. A card is drawn from the remaining cards. Find the probability of getting a card of queen of diamond.

No. of all possible outcomes =52−3=49There is only one queen of diamond∴ Required probability=149

The king, queen and jack of clubs are removed from a deck of $52$ playing cards and the remaining cards are shuffled. A card is drawn from the remaining cards. Find the probability of getting a card of queen of diamond.

No. of all possible outcomes $= 52 - 3 = 49$
There is only one queen of diamond
$∴$ Required probability $= \frac{1}{49}$