The L.C.M and H.C.F of two numbers are 180 and 6 respectively. If ones of the numbers is 30, find the other number.

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Solution

Given:
HCF of two numbers = 6
LCM of two numbers = 180
One of the given number = 30

Product of the two numbers = Product of their HCF and LCM

∴ 30 × other number = 6 × 180
Other number $= \frac{6 \times 180}{30} = 36$
Thus, the required number is 36.

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