The L.C.M. of two numbers is 48. The numbers are in the ratio 2:3. Then sum of the numbers is:
40
Let the numbers be 2xand 3x.
Then, their L.C.M. = 6x.
So, 6x= 48 orx= 8.
The numbers are 16 and 24.
⇒ The numbers are 16 and 24
⇒ Hence, required sum = (16 + 24) = 40