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Question

The L.C.M. of two prime numbers x and y, where (x>y), is 161. The value of 3yx is

A
2
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B
1
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C
1
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D
2
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Solution

The correct option is A 2
The prime factors of 161 are 7 and 23
Since it is given that x>y,x=23,y=7
3yx=3 × 723=2123=2

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