Question

The L.C.M. of two prime numbers $x$ and $y$, where $(x>y)$, is $161$. The value of $3y-x$ is

• A. $-2$
• B. $-1$
• C. $1$
• D. $2$

Answer 1

The correct option is A $-2$

The prime factors of $161$ are $7$ and $23$
Since it is given that $x>y,x=23,y=7$
$\therefore$ $3y-x=3$ $\times$ $7-23=21-23=-2$