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Question

The L.C.M. of (x2+x−6) and (x−2)2 is .

A
(x+3)(x2)2
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B
(x+3)(x+2)2
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C
(x3)(x2)2
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D
(x3)(x+2)2
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Solution

The correct option is A (x+3)(x2)2

First expression, x2+x−6 can be factorized as (x−2)(x+3).

Second expression, (x−2)2 can be factorized as (x−2)(x−2).

So, the LCM of both the expressions = (x+3) (x−2)2


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