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Question

The L.C.M. of xy+yz+zx+y2 and x2+xy+yz+zxis

A
x+y
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B
y+z
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C
(x+y)(y+z)(z+x)
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D
x2+y2
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Solution

The correct option is C x+y
On factorising the given expressions we get, xy+yz+zx+y2
= yz+xy+xz+y2
= z(y+x)+y(x+y)
= (x+y)(z+y)
Also, x2xy+yz+zx
= x(x+y)+z(y+x)
=(y+x)(x+z)
Now, LCM or the common factor of (x+y)(z+y) and (y+x)(x+z)=(x+y)

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