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Surface Energy

The label on ...

Question

The label on the bottle of $H_{2} O_{2}$ solution reads as ' $10$ volume'.
Find the concentration of $H_{2} O_{2}$ expressed in percentage by volume (in nearest integer). The density of $H_{2} O_{2}$ is $1.463$ g/mL.

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Solution

$1$ volume of $H_{2} O_{2}$ will give off $10$ volumes of $O_{2}$ at STP.
The equation is: $2 H_{2} O_{2} \to 2 H_{2} O + O_{2}$ .
$10$ litres correspond to $0.409$ moles of $O_{2}$ .
Therefore, the moles of $H_{2} O_{2}$ are $0.818$ = $27.812$ g of $H_{2} O_{2}$ .
The density of $H_{2} O_{2}$ is $1.463$ g/mL, so $27.78$ grams is about $19.0$ mL or $0.019$ L.
Therefore, the percentage by volume is $\frac{0.019 \times 100}{1} = 1.9$ % by volume.
So, the nearest integer is $2$ %.

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