Question

The Laplace transform of $t{e}^t$ is

• A. $\frac{s}{(s+1{)}^2}$
• B. $\frac{1}{(s-1{)}^2}$
• C. $\frac{s}{(s+1{)}^2}$
• D. $\frac{s}{(s-1)}$

Answer 1

The correct option is B $\frac{1}{(s-1{)}^2}$

L{t}$=\frac{1}{s^2}$
$So,L\left(e^t.t\right)=\frac{1}{(s-1{)}^2}$