The Laplace transform of the function $f (t) = e^{a t} w h e n t > 0$ and where $a$ is constant is

\frac{1}{(s - a)}

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\frac{1}{(s + a)}

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\frac{1}{(s - a)^{- 1}}

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\frac{1}{(s + a)^{- 1}}

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Solution

The correct option is A $\frac{1}{(s - a)}$
Standard result:
$L [e^{a t}] = \frac{1}{s - a}$

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The Laplace transform of the function f(t)=eat when t>0 and where a is constant is

The correct option is A 1(s−a)Standard result: L[eat]=1s−a

The Laplace transform of the function $f (t) = e^{a t} w h e n t > 0$ and where $a$ is constant is

The correct option is A $\frac{1}{(s - a)}$
Standard result:
$L [e^{a t}] = \frac{1}{s - a}$