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Ammonia

The largest b...

Question

The largest bond angle is in :

A s H_{3}

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N H_{3}

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H_{2} O

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P H_{3}

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Solution

The correct option is B $N H_{3}$
In $A s H_{3}$ and $P H_{3}$ bond angle $\approx$ 94(no hybridisation) because of Drago's rule.

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Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

A s H_{3} < P H_{3} < N H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

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