Question

The largest four-digit number, which is a perfect cube is:

• A. $8000$
• B. $9261$
• C. $9999$
• D. $8889$

Answer 1

Answer: (B)

$9261$

Check each option,
$\left(A\right)$ $8000$ is a perfect cube of $20$
$\left(B\right)$ $9261$ is a perfect cube of $21$
$\left(C\right)$ $9999$ is not a perfect cube
$\left(D\right)$ $8889$ is not perfect cube
Since, $9261$ is greater than $8000$ and cube of $22$ is $10648$, thus $9261$ is the greatest four digit perfect cube number.

Hence, option $B$ is correct.