The largest number which divides 92 and 159, leaving remainders of 7 and 6 respectively, is

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

585

No worries! We‘ve got your back. Try BYJU‘S free classes today!

765

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 17
The largest number which divides 92 and 159, leaving remainders 7 and 6 respectively is equal to HCF (92 - 7, 159 - 6)
= HCF (85,153)
$85 = 5 \times 17$
$153 = 3^{2} \times 17$
So, HCF (85,153) = 17
Hence, correct option is a

Suggest Corrections

Similar questions

Find the largest number which divides 320 and 457, leaving remainders 5 and 7 respectively.

230

142

5

7

Join BYJU'S Learning Program