Question

The largest side of a triangle is $3$ times the shorter side & the third side is $2cm$ shorter than the largest side. If the perimeter of the triangle is alteast $61cm$ find the minimum length of the shorter side.

Answer 1

Let $x$ be the shortest side and $3x$ be largest side.

Third side $=3x-2$

Perimeter of triangle is $\ge 61cm$

$\left(x\right)+\left(3x\right)+(3x-2)\ge 61$

$7x-2\ge 61$

$x\ge 9$

Hence the shortest length is $9cm$