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Question

The largest term common to the sequence 1,11,21,31, to 100 terms and 31,36,41,46.. to 100 terms is

A
381
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B
471
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C
281
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D
521
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Solution

The correct option is A 521
1,11,21,31,.....100 terms
31,36,41,46,......100 terms
Last term of first+AP=1+99×10=991
Last term of second AP=31+99×5=526
5265=521
53110=521
Second last term of second AP=521
is largest common to both the sequence.
(D) is correct.

1058312_1114866_ans_b01a876ddf824b038d3a70085a7dca08.png

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