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Question

The largest term of the sequence 1503,4524,9581,16692,... is approximately:

A
4916
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B
481509
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C
491529
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D
641509
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Solution

The correct option is C 491529
500+1×3500+8×3500+27×3500+64×3
y=Tr=r2500+3r3
dydr=(500+3r3)2rr2(0+9r2)(500+3r3)2=0
(500+3r3)2r9r4=0
1000+6r39r3=0
1000=3r3
r=6.937
T7=72500+3×73=491529

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