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Greatest Binomial Coefficients

The last digi...

Question

The last digit of $(8217)^{1114}$ is

A

9

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B

7

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C

3

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D

1

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Solution

The correct option is A $9$
$\begin{matrix} {(8217)}^{1114} u n i t p l a c e o f 7^{1} = 7 u n i t p l a c e o f 7^{2} = 9 u n i t p l a c e o f 7^{3} = 3 u n i t p l a c e o f 7^{4} = 1 u n i t p l a c e o f 7^{5} = 7 u n i t p l a c e o f 7 i s r e p e a t i n g a f t e r a n i n t e r v a l o f 4 \frac{1114}{4} = 278 \frac{2}{4} u n i t p l a c e o f {(8217)}^{1114} w i l b e s a m e a s t h a t o f 7^{2} w h i c h i s 9 . \end{matrix}$

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