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Relation between Odd Numbers Powers of 2

The last digi...

Question

The last digit of the value of the number $2003^{2002} + 2001^{2002}$ is ___.

A

9

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B

1

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C

4

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D

0

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Solution

The correct option is A $0$
Last digit of $(3)^{4 \times n + 2} = 9$
$∴$ last digit of $(2003)^{4 \times 500 + 2}$ is $9$
And last digit of $2001^{2002} = 1$
Therefore last digit of $2003^{2002} + 2001^{2002}$ is $0$ ( as $1 + 9 = 10$ )

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