Question

The last member of $4n+1$ series is an isotope of lead.

• A. True
• B. False

Answer 1

The correct option is B False

The last member of $4n+1$ series is an isotope of $Bi$
$4n+1$ series is neptunium series. It is an artificial series.
${}_{94}P{u}^{241}{\to }_{83}B{i}^{209}$