The last subshell of an element is 3p and there are 3 electrons in it.
a) Write the complete electronic configuration of the element. [ 1 Mark]
b) Identify its period and group. [ 1 Mark]

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Solution

a)
The complete electronic configuration will be:
1s² 2s² 2p⁶ 3s² 3p³
[1 Mark]
b) The element has 3 shells so the element belongs to 3rd period.
The element is a P block element and in p subshell it has 3 electrons so the group number will be 12+3 = 15th.
[1 Mark]

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