The last subshell of an element is 3p and there are 3 electrons in it.

(a) Write the complete electron configuration of the element.
(b) Identify its period and group.

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Solution

(a) Electronic configuration: $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{3}$

(b) Period number = Outermost shell number = 3rd period

Group number = no of electrons in last shell + 12

= 3+12 = 15th group

Period = 3, Group = 15

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