Question

The last two digits in the multiplication of $122\times 123\times 125\times 127\times 129$ is

• A. 20
• B. 50
• C. 30
• D. 40

Answer 1

The correct option is B 50

Divide the given expression by 100 and the expression gets reduced to $22\times 23\times 25\times 27\times 29$ . 50 would be the last two digits here.