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Question

# The latent heat of fusion of ice is 80 calories per gram at 0oC. What is the freezing point of a solution of KCl in water containing 7.45 grams of solute 500 grams of water, assuming that the salt is dissociated to the extent of 95%?

A
Tf=0.73C
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B
Tf=0.92C
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C
Tf=1.46C
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D
Tf=1.84C
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Solution

## The correct option is A Tf=−0.73∘CWe know,Kf(H2O)=RTf2MsolventΔHfusionm×1000 =2×(273.15)2×1880×18×1000 =2×74610.980×1000 =1.865K.Kg/molT′f=0oC−iKf.m =0−(1.95)(1.865)(7.45/74.50.5) =−0.73oCHence, the correct option is A

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