Question

The latent heat of fusion of ice is:

(a) 33.4 $\times {10}^{5}J/Kg$ (b) 22.5 $\times {10}^{5}J/Kg$
(c) 33.4 $\times {10}^{4}J/Kg$ (d) 2.25 $\times {10}^{4}J/Kg$

Answer 1

The latent heat of fusion of ice is 33.4 $\times {10}^{4}J/Kg$.

Latent heat of fusion of ice =

$80cal{g}^{-1}$

$ToconvertcalintoJoulewemultiplyby4.184$

$80\times 4.184J\times {10}^{3}K{g}^{-1}$

$=33.4\times \frac{{10}^{4}J}{Kg}$

Latent heat of fusion is defined as the amount of energy that must be supplied to a solid substance in order to create a change in its physical state and convert it into liquid (when the pressure is constant)

Hence, (C) 33.4 $\times {10}^{4}J/Kg$ is the correct answer.