The latent heat of vaporisation of water is- a 2-25 - 106 J-Kg a 3-34 - 106 J-Kg c 2-25 - 104 J-Kg d 33-4 - 105 J-Kg

The latent heat of vaporisation of water is 2.25 × 10^6 J/Kg. ...

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Latent Heat of Vaporisation

The latent he...

Question

The latent heat of vaporisation of water is:
(a) $2.25 \times 10^{6} J / K g$ (a) $3.34 \times 10^{6} J / K g$
(c) $2.25 \times 10^{4} J / K g$ (d) $33.4 \times 10^{5} J / K g$

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The latent heat of fusion of ice is:

(a) 33.4 $\times 10^{5} J / K g$ (b) 22.5 $\times 10^{5} J / K g$
(c) 33.4 $\times 10^{4} J / K g$ (d) 2.25 $\times 10^{4} J / K g$

What is meant by saying that the latent heat of vaporisation of water is 22.5 $\times 10^{5}$ J/Kg?

1

100^{0} C

1 a t m

(100 k P a)

1000 k g / m^{3}

0.6 k g / m^{3}

2.25 \times 10^{6} J / k g

^{- 3}

^{- 3}

2.25 \times 10^{6} J k g^{- 1}

$Calculate the amount of heat required to convert 1.00 kg of ice at -10°C$
$at normal pressure to steam at 100°C.$

$The specific heat capacity of ice = 2100 J k g^{- 1} K^{- 1}$

$Latent heat of fusion of ice = 3.36 \times 10^{5} J k g^{- 1}$

$The specific heat capacity of water = 4200 J k g^{- 1} K^{- 1}$

$Latent heat of vaporization of water = 2.25 \times 10^{6} J k g - 1$

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