The lateral area of the frustum of a right circular cone is calculated by using the formula _________________.

π (R + r) l

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π (R - r) l

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\frac{π}{2} (R + r) l

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\frac{π}{2} (R - r) l

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Solution

The correct option is B $π (R + r) l$
The lateral area of the frustum of a right circular cone is equal to one-half of the sum of the circumferences of the bases multiplied by slant height.
Lateral area $= \frac{1}{2} (2 π R + 2 π r) l$
$= (π R + π r) l$
$= π (R + r) l$

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The lateral area of the frustum of a right circular cone is calculated by using the formula _________________.

The correct option is B π(R+r)lThe lateral area of the frustum of a right circular cone is equal to one-half of the sum of the circumferences of the bases multiplied by slant height.Lateral area=12(2πR+2πr)l =(πR+πr)l =π(R+r)l

The correct option is B $π (R + r) l$
The lateral area of the frustum of a right circular cone is equal to one-half of the sum of the circumferences of the bases multiplied by slant height.
Lateral area $= \frac{1}{2} (2 π R + 2 π r) l$
$= (π R + π r) l$
$= π (R + r) l$