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Question

The lateral surface area of a hollow cylinder is 4,224 cm2. It is cut along its height and formed a rectangular sheet of width 33 cm. Find the perimeter of the rectangular sheet.

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Solution

Given:
The lateral surface area of hollow cylinder =4224 cm2.
The width of rectangular sheet (b)=33 cm.

Let the length of rectangular sheet be l.
According to the given condition,
lateral surface area of cylinder = Area of rectangular sheet
4224=l×b
l=422433 cm
l=128 cm

Now, perimeter of rectangular sheet =2×(l+b)
=2×(128+33) cm
=322 cm
Hence, the perimeter of rectangular sheet is 322 cm.

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