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Byju's Answer
Standard XII
Chemistry
Enthalpy
The lattice e...
Question
The lattice energy of
N
a
C
l
(
s
)
is
−
790
k
J
.
m
o
l
−
1
and enthalpy of hydration is
−
785
k
J
.
m
o
l
−
1
. Calculate the enthalpy of the solution of
N
a
C
l
(
s
)
.
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Solution
E
nthalpy of solution
=
E
nthalpy of hydration
−
Lattice energy of
NaCl(s)
=
−
785
−
(
−
790
)
=
5
k
J
/
m
o
l
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1
Similar questions
Q.
The lattice enthalpy of solid
N
a
C
l
is
772
k
J
m
o
l
−
1
and enthalpy of solution is
2
k
J
m
o
l
−
1
. If the hydration enthalpy of
N
a
+
and
C
l
−
ions are in the ratio of
3
:
2.5
, what is the enthalpy of hydration of chloride ion?
Q.
The change in enthalpy for hydration of ( i ) the chloride ion ; ( ii ) the iodide ion are :
Given :
* enthalpy change of solution of NaCl(s)
=
−
2
kJ / mol.
* enthalpy change of solution of NaI(s)
=
+
2
kJ / mol.
* enthalpy change of hydration of
N
a
+
(
g
)
=
−
390
kJ / mol.
* lattice enthalpy of NaCl
=
−
772
kJ / mol.
* lattice enthalpy of NaI
=
−
699
kJ / mol.
Q.
The lattice energy of solid
N
a
C
l
is
180
k
c
a
l
m
o
l
−
1
. The dissolution of the solid in water in the form of ions is endothermic to the extent of 1
k
c
a
l
m
o
l
−
1
. If the hydration energies of
N
a
+
and
C
l
−
are in the ratio 6:5, then the enthalpy of hydration of
N
a
+
ion is:
Q.
The lattice energy of solid
K
C
l
is 181 kcal/mol. The enthalpy of solution of
K
C
l
in water is 1 kcal/mol. If the hydration enthalpies of potassium and chloride ions are in the ratio
2
:
1
, what is the hydration enthalpy (kcal/mol) of potassium ions?
Q.
Calculate the hydration enthalpy of ions for
N
a
C
l
(
s
)
from the following data.
Δ
l
a
t
t
i
c
e
H
=
+
788
k
J
m
o
l
−
1
Δ
s
o
l
H
=
+
4
k
J
m
o
l
−
1
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