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Question

The lattice energy of solid KCl is 181 kcal/mol. The enthalpy of solution of KCl in water is 1 kcal/mol. If the hydration enthalpies of potassium and chloride ions are in the ratio 2:1, what is the hydration enthalpy (kcal/mol) of potassium ions?

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Solution

ΔHsolution=ΔHlattice+ΔHhydration
1=181+ΔHhyd K++ΔHhyd Cl
180=ΔHhyd K++12ΔHhyd K+
180=32ΔHhyd K+
180×23=ΔHhyd K+
ΔHhyd K+=120kcal/mol

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