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Lattice Energy

The lattice e...

Question

The lattice enthalpy of KI will be, if the enthalpy of (I) Δ_fH^°(KI) = –78.0 kcal mol^{-1} (II) Ionisation energy of K to K+ is 4.0 eV (III) Dissociation energy of I_2 to I is 28.0 kcal mol^{-1} (IV) Sublimation energy of K is 20.0 kcal mol^{-1} (V) Electron gain enthalpy for I to I^- is –70.0 kcal mol^{-1} (VI) Sublimation energy of I2 is 14.0 kcal mol^{-1} (1 eV = 23.0 kcal mol^{-1}) Options: a) +14.1 kcal mol^{-1} b) -14.1 kcal mol^{-1} c) -141 kcal mol^{-1} d) +141 kcal mol^{-1

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K I

- 78.31 k c a l m o l^{- 1}

I E (K) = 4.3 e V

E A (I) = - 73.4 k c a l m o l^{- 1}

I_{2}

36.1 k c a l m o l^{- 1}

K

21.51 k c a l m o l^{- 1}

e V

=

23.06 k c a l

K I

- 78.31 {kcal mol}^{- 1}

I_{1} (K) = 4.3 eV E_{1} (I) = 73.4 {kcal mol}^{- 1} Bond dissociation energy of I_{2} = 36.1 {kcal mol}^{- 1} Sublimation energy of K = 21.51 {kcal mol}^{- 1}

C H_{3} - H

103 k c a l m o l^{- 1}

C H_{4} (g)

- 17.88 k c a l m o l^{- 1} .

H_{2} (g)

H

103 k c a l / m o l .

F_{2}

X e F_{4} \to X e^{+} + F^{-} + F_{2} + F

- 186

+

^{-}

- 97

- 85

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