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Molarity

The lattice e...

Question

The lattice enthalpy of solid $N a C l$ is $772 k J m o l^{- 1}$ and of solution is $2 k J m o l^{- 1}$ . If the hydration enthalpy of $N a^{+}$ and $C l^{-}$ ions are in the ratio of $3 : 2.5$ , then the enthalpy of hydration of chloride ion is:

- 140 k J m o l^{- 1}

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- 350 k J m o l^{- 1}

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- 351.81 k J m o l^{- 1}

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none of the above

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Solution

The correct option is B $- 350 k J m o l^{- 1}$
The lattice enthalpy of solid $N a C l$ is $772 k J m o l^{- 1}$ , enthalpy of solution is $2 k J m o l^{- 1}$ .
Also, hydration enthalpy of $N a^{+}$ and $C l^{-}$ ions are in the ratio of $3 : 2.5$ .
So, the enthalpy of hydration of chloride ion $= \frac{(772 - 2)}{5.5} \times 2.5 = 350 k J / m o l$

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