The latus rectum of parabola $y^{2} = 5 x + 4 y + 1$ is

$\frac{5}{4}$

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$10$

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$5$

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$\frac{5}{2}$

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Solution

The correct option is C
$5$

$y^{2} - 4 y + 4 = 5 x + 5 \Rightarrow (y - 2)^{2} = 5 (x + 1)$

Obviously, latus rectum is 5.

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