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Question

The latus-rectum of the hyperbola 16x2 − 9y2 = 144 is
(a) 16/3
(b) 32/3
(c) 8/3
(d) 4/3

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Solution

(b) 32/3

The standard form of the hyperbola 16x2-9y2=144 is x29-y216=1.
Here, a2=9, b2=16
Latus rectum of the hyperbola = 2b2a=2×163=323

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