Question

The LCM and HCF of two numbers are 1001 and 7 respectively. How many such pairs are possible?

• A. 0
• B. 1
• C. 2
• D. None of these
  

Answer 1

Answer: (C)

2

$LCM=1001$ and $HCF=7$

Let the two numbers be $x$ and $y.$

Therefore,

$x=7a$ and $y=7b$, where $a$ and $b$ are co-primes.

We have,

$x\times y=LCM\times HCF$

$7a\times 7b=1001\times 7$

$ab=143$

$(a,b)=(1,143)$ or $(11,13)$

There are two pairs of numbers.