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Question

The LCM and HCF of two numbers are 180 and 6 respectively.If one of the numbers is 30, find the other number.

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Solution

Given : LCM and HCF of two numbers are 180 and 6.
One number =30
Find : another number =?
Solution :
we know that two numbers product is equal their HCF and LCM product
Let another number =x
x×30=180×6

x=180×630

x=36

so another number is 36.

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