wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The LCM and HCF of two numbers are 4125 and 25 respectively. One number is 375. Find by how much is the second number less than the first ?

Open in App
Solution

LCM = 4125
HCF = 25
1st Number = 375
Let, 2nd Number = x
We all know that, product of two numbers is equal to the product of LCM and HCF of these two numbers
So,
375 × x = 4125 × 25
x = ( 4125 × 25 ) / 375
x = ( 1,03,125 ) / 375
x = 275.

Difference of both numbers = 375 - 275 =100
Hence, Second number is 100 less than the first number.


flag
Suggest Corrections
thumbs-up
30
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Special Factors and Multiples
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon