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Question

The LCM and HCF of two polynomials are respectively (2a5)2(a+1)and(2a5) If one of the polynomials is 4a220a+25 the other one is

A
4a2+20a+5
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B
4a225
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C
2a2+3a5
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D
2a23a5
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Solution

The correct option is D 2a23a5
LCM=(2a5)(2a5)(a+1)
HCF=(2a5)
One polynomial=4a220a+25
4a210a10a+25
2a(2a5)5(2a5)
(2a5)(2a5)
LCM×HCF=Productoftwonumber
Let another number is x
(2a5)(2a5)(a+1)(2a5)=(2a5)(2a5)×x
x=(2a5)(2a5)(a+1)(2a5)(2a5)(2a5)
x=(a+1)(2a5)2a23a5

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